Base | Representation |
---|---|
bin | 11000001111100011… |
… | …01011001101011011 |
3 | 1020121001201000111221 |
4 | 30013301223031123 |
5 | 203123413130233 |
6 | 5551300232511 |
7 | 640350525634 |
oct | 140761531533 |
9 | 36531630457 |
10 | 13015364443 |
11 | 5579919a44 |
12 | 263299b737 |
13 | 12c56211a3 |
14 | 8b680888b |
15 | 51298942d |
hex | 307c6b35b |
13015364443 has 2 divisors, whose sum is σ = 13015364444. Its totient is φ = 13015364442.
The previous prime is 13015364431. The next prime is 13015364447. The reversal of 13015364443 is 34446351031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13015364443 - 213 = 13015356251 is a prime.
It is a super-3 number, since 3×130153644433 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13015364399 and 13015364408.
It is not a weakly prime, because it can be changed into another prime (13015364447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507682221 + 6507682222.
It is an arithmetic number, because the mean of its divisors is an integer number (6507682222).
Almost surely, 213015364443 is an apocalyptic number.
13015364443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13015364443 is an equidigital number, since it uses as much as digits as its factorization.
13015364443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 34.
The spelling of 13015364443 in words is "thirteen billion, fifteen million, three hundred sixty-four thousand, four hundred forty-three".
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