Base | Representation |
---|---|
bin | 11101100110000000111001… |
… | …010010010011000000101011 |
3 | 122001211202111001000100121220 |
4 | 131212000321102103000223 |
5 | 114024432232402121010 |
6 | 1140452402530233123 |
7 | 36262302225163251 |
oct | 3546007122230053 |
9 | 561752431010556 |
10 | 130155650035755 |
11 | 38520779326913 |
12 | 12721053a257a3 |
13 | 578181855a566 |
14 | 241d7d20a05d1 |
15 | 100a9a91d2970 |
hex | 76603949302b |
130155650035755 has 16 divisors (see below), whose sum is σ = 208276633857024. Its totient is φ = 69407148752480.
The previous prime is 130155650035739. The next prime is 130155650035883. The reversal of 130155650035755 is 557530056551031.
It is not a de Polignac number, because 130155650035755 - 24 = 130155650035739 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130155650035698 and 130155650035707.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 574753851 + ... + 574980260.
It is an arithmetic number, because the mean of its divisors is an integer number (13017289616064).
Almost surely, 2130155650035755 is an apocalyptic number.
130155650035755 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
130155650035755 is a deficient number, since it is larger than the sum of its proper divisors (78120983821269).
130155650035755 is a wasteful number, since it uses less digits than its factorization.
130155650035755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1149741666.
The product of its (nonzero) digits is 5906250, while the sum is 51.
The spelling of 130155650035755 in words is "one hundred thirty trillion, one hundred fifty-five billion, six hundred fifty million, thirty-five thousand, seven hundred fifty-five".
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