Base | Representation |
---|---|
bin | 1011110101101010110001… |
… | …1101010001100100101011 |
3 | 1201002101020022121122122120 |
4 | 2331122230131101210223 |
5 | 3201231041412342222 |
6 | 43403432552522323 |
7 | 2512264402450206 |
oct | 275325435214453 |
9 | 51071208548576 |
10 | 13016644262187 |
11 | 4169367385285 |
12 | 15628679b03a3 |
13 | 735606066a77 |
14 | 33001a78293d |
15 | 1788d59e015c |
hex | bd6ac75192b |
13016644262187 has 4 divisors (see below), whose sum is σ = 17355525682920. Its totient is φ = 8677762841456.
The previous prime is 13016644262179. The next prime is 13016644262221. The reversal of 13016644262187 is 78126244661031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13016644262187 - 23 = 13016644262179 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13016644262117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2169440710362 + ... + 2169440710367.
It is an arithmetic number, because the mean of its divisors is an integer number (4338881420730).
Almost surely, 213016644262187 is an apocalyptic number.
13016644262187 is a deficient number, since it is larger than the sum of its proper divisors (4338881420733).
13016644262187 is an equidigital number, since it uses as much as digits as its factorization.
13016644262187 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4338881420732.
The product of its (nonzero) digits is 2322432, while the sum is 51.
The spelling of 13016644262187 in words is "thirteen trillion, sixteen billion, six hundred forty-four million, two hundred sixty-two thousand, one hundred eighty-seven".
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