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130184836553 is a prime number
BaseRepresentation
bin111100100111110011…
…1101111010111001001
3110110000210201220201002
41321033213233113021
54113104304232203
6135450040504345
712256046565302
oct1711747572711
9413023656632
10130184836553
1150235a45612
122129277b0b5
13c37927cc85
14642dc617a9
1535be1c4d88
hex1e4f9ef5c9

130184836553 has 2 divisors, whose sum is σ = 130184836554. Its totient is φ = 130184836552.

The previous prime is 130184836547. The next prime is 130184836583. The reversal of 130184836553 is 355638481031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122774553664 + 7410282889 = 350392^2 + 86083^2 .

It is a cyclic number.

It is not a de Polignac number, because 130184836553 - 26 = 130184836489 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130184836498 and 130184836507.

It is not a weakly prime, because it can be changed into another prime (130184836513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65092418276 + 65092418277.

It is an arithmetic number, because the mean of its divisors is an integer number (65092418277).

Almost surely, 2130184836553 is an apocalyptic number.

It is an amenable number.

130184836553 is a deficient number, since it is larger than the sum of its proper divisors (1).

130184836553 is an equidigital number, since it uses as much as digits as its factorization.

130184836553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 47.

The spelling of 130184836553 in words is "one hundred thirty billion, one hundred eighty-four million, eight hundred thirty-six thousand, five hundred fifty-three".