Base | Representation |
---|---|
bin | 11101100110101011001110… |
… | …011000110110011111111001 |
3 | 122002000002210121110100202002 |
4 | 131212223032120312133321 |
5 | 114031203323403411441 |
6 | 1140525320555150345 |
7 | 36265501444032653 |
oct | 3546531630663771 |
9 | 562002717410662 |
10 | 130201101232121 |
11 | 38538a82345417 |
12 | 12729a194453b5 |
13 | 5785baca96aaa |
14 | 2421aa461d6d3 |
15 | 100bc69548b9b |
hex | 766ace6367f9 |
130201101232121 has 4 divisors (see below), whose sum is σ = 130625209054032. Its totient is φ = 129776993410212.
The previous prime is 130201101232093. The next prime is 130201101232133. The reversal of 130201101232121 is 121232101102031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130201101232121 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130201101232093 and 130201101232102.
It is not an unprimeable number, because it can be changed into a prime (130201101232721) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212053910495 + ... + 212053911108.
It is an arithmetic number, because the mean of its divisors is an integer number (32656302263508).
Almost surely, 2130201101232121 is an apocalyptic number.
It is an amenable number.
130201101232121 is a deficient number, since it is larger than the sum of its proper divisors (424107821911).
130201101232121 is an equidigital number, since it uses as much as digits as its factorization.
130201101232121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 424107821910.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 130201101232121 its reverse (121232101102031), we get a palindrome (251433202334152).
The spelling of 130201101232121 in words is "one hundred thirty trillion, two hundred one billion, one hundred one million, two hundred thirty-two thousand, one hundred twenty-one".
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