Base | Representation |
---|---|
bin | 1011110101110111110000… |
… | …0000010101010010100011 |
3 | 1201002201012222202100011101 |
4 | 2331131330000111102203 |
5 | 3201310204320224123 |
6 | 43405210301455231 |
7 | 2512446603546322 |
oct | 275357400252243 |
9 | 51081188670141 |
10 | 13020126336163 |
11 | 416a893978a71 |
12 | 1563479b71517 |
13 | 735a3c597c7b |
14 | 33026add60b9 |
15 | 178a3b55aaad |
hex | bd77c0154a3 |
13020126336163 has 2 divisors, whose sum is σ = 13020126336164. Its totient is φ = 13020126336162.
The previous prime is 13020126336149. The next prime is 13020126336167. The reversal of 13020126336163 is 36163362102031.
13020126336163 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (36163362102031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13020126336163 - 217 = 13020126205091 is a prime.
It is not a weakly prime, because it can be changed into another prime (13020126336167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510063168081 + 6510063168082.
It is an arithmetic number, because the mean of its divisors is an integer number (6510063168082).
Almost surely, 213020126336163 is an apocalyptic number.
13020126336163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13020126336163 is an equidigital number, since it uses as much as digits as its factorization.
13020126336163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 37.
Adding to 13020126336163 its reverse (36163362102031), we get a palindrome (49183488438194).
The spelling of 13020126336163 in words is "thirteen trillion, twenty billion, one hundred twenty-six million, three hundred thirty-six thousand, one hundred sixty-three".
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