130204420000441 has 4 divisors (see below), whose sum is σ = 130206441904000. Its totient is φ = 130202398096884.

The previous prime is 130204420000439. The next prime is 130204420000483. The reversal of 130204420000441 is 144000024402031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130204420000441 - 2¹ = 130204420000439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130204420040441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1010855181 + ... + 1010983978.

It is an arithmetic number, because the mean of its divisors is an integer number (32551610476000).

Almost surely, 2^{130204420000441} is an apocalyptic number.

It is an amenable number.

130204420000441 is a deficient number, since it is larger than the sum of its proper divisors (2021903559).

130204420000441 is an equidigital number, since it uses as much as digits as its factorization.

130204420000441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2021903558.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 130204420000441 its reverse (144000024402031), we get a palindrome (274204444402472).

The spelling of 130204420000441 in words is "one hundred thirty trillion, two hundred four billion, four hundred twenty million, four hundred forty-one", and thus it is an aban number.