Base | Representation |
---|---|
bin | 11101100110110100101111… |
… | …001110011001110110110011 |
3 | 122002001002011111000002020011 |
4 | 131212310233032121312303 |
5 | 114031340233322133112 |
6 | 1140534130325155351 |
7 | 36266312535421312 |
oct | 3546645716316663 |
9 | 562032144002204 |
10 | 130211315817907 |
11 | 385423441a4955 |
12 | 1272b9aa25bb57 |
13 | 5786b4a0774ac |
14 | 2422393080279 |
15 | 100c166192aa7 |
hex | 766d2f399db3 |
130211315817907 has 2 divisors, whose sum is σ = 130211315817908. Its totient is φ = 130211315817906.
The previous prime is 130211315817889. The next prime is 130211315817931. The reversal of 130211315817907 is 709718513112031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130211315817907 - 235 = 130176956079539 is a prime.
It is not a weakly prime, because it can be changed into another prime (130211315817977) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65105657908953 + 65105657908954.
It is an arithmetic number, because the mean of its divisors is an integer number (65105657908954).
Almost surely, 2130211315817907 is an apocalyptic number.
130211315817907 is a deficient number, since it is larger than the sum of its proper divisors (1).
130211315817907 is an equidigital number, since it uses as much as digits as its factorization.
130211315817907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 317520, while the sum is 49.
Adding to 130211315817907 its reverse (709718513112031), we get a palindrome (839929828929938).
The spelling of 130211315817907 in words is "one hundred thirty trillion, two hundred eleven billion, three hundred fifteen million, eight hundred seventeen thousand, nine hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •