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130212113121313 is a prime number
BaseRepresentation
bin11101100110110101011110…
…101111111000000000100001
3122002001011020001021021212221
4131212311132233320000201
5114031343401424340223
61140534341410151041
736266341356404116
oct3546653657700041
9562034201237787
10130212113121313
1138542713263793
121272bb91282481
135786c462c4b62
14242242ad0690d
15100c1b1185b5d
hex766d5ebf8021

130212113121313 has 2 divisors, whose sum is σ = 130212113121314. Its totient is φ = 130212113121312.

The previous prime is 130212113121283. The next prime is 130212113121329. The reversal of 130212113121313 is 313121311212031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76884978854464 + 53327134266849 = 8768408^2 + 7302543^2 .

It is a cyclic number.

It is not a de Polignac number, because 130212113121313 - 25 = 130212113121281 is a prime.

It is a super-2 number, since 2×1302121131213132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130212113121373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106056560656 + 65106056560657.

It is an arithmetic number, because the mean of its divisors is an integer number (65106056560657).

Almost surely, 2130212113121313 is an apocalyptic number.

It is an amenable number.

130212113121313 is a deficient number, since it is larger than the sum of its proper divisors (1).

130212113121313 is an equidigital number, since it uses as much as digits as its factorization.

130212113121313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 130212113121313 its reverse (313121311212031), we get a palindrome (443333424333344).

The spelling of 130212113121313 in words is "one hundred thirty trillion, two hundred twelve billion, one hundred thirteen million, one hundred twenty-one thousand, three hundred thirteen".