130212232441 has 4 divisors (see below), whose sum is σ = 130236792192. Its totient is φ = 130187672692.

The previous prime is 130212232427. The next prime is 130212232459. The reversal of 130212232441 is 144232212031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130212232441 - 2¹³ = 130212224249 is a prime.

It is a super-3 number, since 3×130212232441³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130212232471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12271921 + ... + 12282526.

It is an arithmetic number, because the mean of its divisors is an integer number (32559198048).

Almost surely, 2^130212232441 is an apocalyptic number.

It is an amenable number.

130212232441 is a deficient number, since it is larger than the sum of its proper divisors (24559751).

130212232441 is an equidigital number, since it uses as much as digits as its factorization.

130212232441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24559750.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 130212232441 its reverse (144232212031), we get a palindrome (274444444472).

The spelling of 130212232441 in words is "one hundred thirty billion, two hundred twelve million, two hundred thirty-two thousand, four hundred forty-one".