Base | Representation |
---|---|
bin | 10010111100101101000… |
… | …000001001001011100011 |
3 | 11121111000200111220020021 |
4 | 102330231000021023203 |
5 | 132313230301244021 |
6 | 2434105035054311 |
7 | 163034666153263 |
oct | 22745500111343 |
9 | 4544020456207 |
10 | 1302130103011 |
11 | 462259551101 |
12 | 1904408a1397 |
13 | 95a374c511a |
14 | 4704842d7a3 |
15 | 23d10e36c41 |
hex | 12f2d0092e3 |
1302130103011 has 4 divisors (see below), whose sum is σ = 1303369048024. Its totient is φ = 1300891158000.
The previous prime is 1302130102963. The next prime is 1302130103033. The reversal of 1302130103011 is 1103010312031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1302130103011 - 229 = 1301593232099 is a prime.
It is a super-2 number, since 2×13021301030112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1302130133011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 619470930 + ... + 619473031.
It is an arithmetic number, because the mean of its divisors is an integer number (325842262006).
Almost surely, 21302130103011 is an apocalyptic number.
1302130103011 is a deficient number, since it is larger than the sum of its proper divisors (1238945013).
1302130103011 is a wasteful number, since it uses less digits than its factorization.
1302130103011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1238945012.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1302130103011 its reverse (1103010312031), we get a palindrome (2405140415042).
The spelling of 1302130103011 in words is "one trillion, three hundred two billion, one hundred thirty million, one hundred three thousand, eleven".
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