130213410433 has 4 divisors (see below), whose sum is σ = 130365352260. Its totient is φ = 130061468608.

The previous prime is 130213410401. The next prime is 130213410449. The reversal of 130213410433 is 334014312031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 127215628929 + 2997781504 = 356673^2 + 54752^2 .

It is a cyclic number.

It is not a de Polignac number, because 130213410433 - 2⁵ = 130213410401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130213410398 and 130213410407.

It is not an unprimeable number, because it can be changed into a prime (130213410533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75969628 + ... + 75971341.

It is an arithmetic number, because the mean of its divisors is an integer number (32591338065).

Almost surely, 2^130213410433 is an apocalyptic number.

It is an amenable number.

130213410433 is a deficient number, since it is larger than the sum of its proper divisors (151941827).

130213410433 is an equidigital number, since it uses as much as digits as its factorization.

130213410433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151941826.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 130213410433 its reverse (334014312031), we get a palindrome (464227722464).

The spelling of 130213410433 in words is "one hundred thirty billion, two hundred thirteen million, four hundred ten thousand, four hundred thirty-three".