Base | Representation |
---|---|
bin | 1011110101111100100100… |
… | …0111010001001111110001 |
3 | 1201002211120011000021122202 |
4 | 2331133021013101033301 |
5 | 3201320332010001431 |
6 | 43405542513312545 |
7 | 2512523632530602 |
oct | 275371107211761 |
9 | 51084504007582 |
10 | 13021420000241 |
11 | 4170398138a34 |
12 | 156377b265755 |
13 | 735bb75c5083 |
14 | 330350b47da9 |
15 | 178ab4de88cb |
hex | bd7c91d13f1 |
13021420000241 has 2 divisors, whose sum is σ = 13021420000242. Its totient is φ = 13021420000240.
The previous prime is 13021420000151. The next prime is 13021420000279. The reversal of 13021420000241 is 14200002412031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10117940318641 + 2903479681600 = 3180871^2 + 1703960^2 .
It is a cyclic number.
It is not a de Polignac number, because 13021420000241 - 238 = 12746542093297 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (13021420000541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510710000120 + 6510710000121.
It is an arithmetic number, because the mean of its divisors is an integer number (6510710000121).
Almost surely, 213021420000241 is an apocalyptic number.
It is an amenable number.
13021420000241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13021420000241 is an equidigital number, since it uses as much as digits as its factorization.
13021420000241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 13021420000241 its reverse (14200002412031), we get a palindrome (27221422412272).
The spelling of 13021420000241 in words is "thirteen trillion, twenty-one billion, four hundred twenty million, two hundred forty-one", and thus it is an aban number.
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