Base | Representation |
---|---|
bin | 1011110101111110101110… |
… | …1111100110111001000001 |
3 | 1201002220001122021010111101 |
4 | 2331133223233212321001 |
5 | 3201323024224000001 |
6 | 43410120310214401 |
7 | 2512544216123500 |
oct | 275375357467101 |
9 | 51086048233441 |
10 | 13022001000001 |
11 | 4170666099724 |
12 | 1563901954401 |
13 | 735c7aa9a606 |
14 | 3303a7d86837 |
15 | 178aeae11a01 |
hex | bd7ebbe6e41 |
13022001000001 has 48 divisors (see below), whose sum is σ = 15581968477824. Its totient is φ = 10842948458496.
The previous prime is 13022000999993. The next prime is 13022001000011. The reversal of 13022001000001 is 10000010022031.
It is not a de Polignac number, because 13022001000001 - 23 = 13022000999993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13022001000011) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5911029766 + ... + 5911031968.
It is an arithmetic number, because the mean of its divisors is an integer number (324624343288).
Almost surely, 213022001000001 is an apocalyptic number.
It is an amenable number.
13022001000001 is a deficient number, since it is larger than the sum of its proper divisors (2559967477823).
13022001000001 is a wasteful number, since it uses less digits than its factorization.
13022001000001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5910 (or 5903 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 10.
Adding to 13022001000001 its reverse (10000010022031), we get a palindrome (23022011022032).
The spelling of 13022001000001 in words is "thirteen trillion, twenty-two billion, one million, one", and thus it is an aban number and an uban number.
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