Base | Representation |
---|---|
bin | 1011110101111110110011… |
… | …1100010101010100100001 |
3 | 1201002220010001002222111202 |
4 | 2331133230330111110201 |
5 | 3201323044401104441 |
6 | 43410122305250545 |
7 | 2512544552103356 |
oct | 275375474252441 |
9 | 51086101088452 |
10 | 13022021113121 |
11 | 4170676486a39 |
12 | 1563908633a55 |
13 | 735c81cc0377 |
14 | 3303aa90062d |
15 | 178aeca8619b |
hex | bd7ecf15521 |
13022021113121 has 2 divisors, whose sum is σ = 13022021113122. Its totient is φ = 13022021113120.
The previous prime is 13022021113117. The next prime is 13022021113217. The reversal of 13022021113121 is 12131112022031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10411663877521 + 2610357235600 = 3226711^2 + 1615660^2 .
It is a cyclic number.
It is not a de Polignac number, because 13022021113121 - 22 = 13022021113117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13022021113093 and 13022021113102.
It is not a weakly prime, because it can be changed into another prime (13022021113421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511010556560 + 6511010556561.
It is an arithmetic number, because the mean of its divisors is an integer number (6511010556561).
Almost surely, 213022021113121 is an apocalyptic number.
It is an amenable number.
13022021113121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022021113121 is an equidigital number, since it uses as much as digits as its factorization.
13022021113121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 13022021113121 its reverse (12131112022031), we get a palindrome (25153133135152).
The spelling of 13022021113121 in words is "thirteen trillion, twenty-two billion, twenty-one million, one hundred thirteen thousand, one hundred twenty-one".
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