Base | Representation |
---|---|
bin | 1011110101111110110110… |
… | …0101111100110111011001 |
3 | 1201002220010210122021001101 |
4 | 2331133231211330313121 |
5 | 3201323110144214001 |
6 | 43410123335151401 |
7 | 2512545043612531 |
oct | 275375545746731 |
9 | 51086123567041 |
10 | 13022032023001 |
11 | 4170681658771 |
12 | 1563910215561 |
13 | 735c84340111 |
14 | 3303ac1404c1 |
15 | 178aed9dda01 |
hex | bd7ed97cdd9 |
13022032023001 has 2 divisors, whose sum is σ = 13022032023002. Its totient is φ = 13022032023000.
The previous prime is 13022032022927. The next prime is 13022032023023. The reversal of 13022032023001 is 10032023022031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11296287390025 + 1725744632976 = 3360995^2 + 1313676^2 .
It is a cyclic number.
It is not a de Polignac number, because 13022032023001 - 237 = 12884593069529 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13022032023001.
It is not a weakly prime, because it can be changed into another prime (13022032023701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511016011500 + 6511016011501.
It is an arithmetic number, because the mean of its divisors is an integer number (6511016011501).
Almost surely, 213022032023001 is an apocalyptic number.
It is an amenable number.
13022032023001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022032023001 is an equidigital number, since it uses as much as digits as its factorization.
13022032023001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13022032023001 its reverse (10032023022031), we get a palindrome (23054055045032).
The spelling of 13022032023001 in words is "thirteen trillion, twenty-two billion, thirty-two million, twenty-three thousand, one".
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