Base | Representation |
---|---|
bin | 111100101000111001… |
… | …0000111001111101011 |
3 | 110110010022222210212101 |
4 | 1321101302013033223 |
5 | 4113143101012001 |
6 | 135453414154231 |
7 | 12260000113441 |
oct | 1712162071753 |
9 | 413108883771 |
10 | 130221110251 |
11 | 50254470581 |
12 | 212a2952977 |
13 | c3839406bb |
14 | 64349c4b91 |
15 | 35c248ca01 |
hex | 1e51c873eb |
130221110251 has 2 divisors, whose sum is σ = 130221110252. Its totient is φ = 130221110250.
The previous prime is 130221110233. The next prime is 130221110263. The reversal of 130221110251 is 152011122031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130221110251 is a prime.
It is not a weakly prime, because it can be changed into another prime (130221110651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65110555125 + 65110555126.
It is an arithmetic number, because the mean of its divisors is an integer number (65110555126).
Almost surely, 2130221110251 is an apocalyptic number.
130221110251 is a deficient number, since it is larger than the sum of its proper divisors (1).
130221110251 is an equidigital number, since it uses as much as digits as its factorization.
130221110251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 130221110251 its reverse (152011122031), we get a palindrome (282232232282).
The spelling of 130221110251 in words is "one hundred thirty billion, two hundred twenty-one million, one hundred ten thousand, two hundred fifty-one".
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