Base | Representation |
---|---|
bin | 1011110110000010011101… |
… | …1001000100011100110011 |
3 | 1201002222122101022012201222 |
4 | 2331200213121010130303 |
5 | 3201332101420142343 |
6 | 43410403455215255 |
7 | 2512611060133334 |
oct | 275404731043463 |
9 | 51088571265658 |
10 | 13023001724723 |
11 | 4171029a67a51 |
12 | 1563b40b1752b |
13 | 7360aa1cc613 |
14 | 330460c4228b |
15 | 178b58bd7a68 |
hex | bd827644733 |
13023001724723 has 2 divisors, whose sum is σ = 13023001724724. Its totient is φ = 13023001724722.
The previous prime is 13023001724701. The next prime is 13023001724743. The reversal of 13023001724723 is 32742710032031.
13023001724723 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13023001724723 is a prime.
It is not a weakly prime, because it can be changed into another prime (13023001724743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511500862361 + 6511500862362.
It is an arithmetic number, because the mean of its divisors is an integer number (6511500862362).
Almost surely, 213023001724723 is an apocalyptic number.
13023001724723 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023001724723 is an equidigital number, since it uses as much as digits as its factorization.
13023001724723 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42336, while the sum is 35.
Adding to 13023001724723 its reverse (32742710032031), we get a palindrome (45765711756754).
The spelling of 13023001724723 in words is "thirteen trillion, twenty-three billion, one million, seven hundred twenty-four thousand, seven hundred twenty-three".
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