Base | Representation |
---|---|
bin | 1011110110000010011111… |
… | …1101010010111011011011 |
3 | 1201002222200001011200110202 |
4 | 2331200213331102323123 |
5 | 3201332111333034321 |
6 | 43410404434532415 |
7 | 2512611233635025 |
oct | 275404775227333 |
9 | 51088601150422 |
10 | 13023011221211 |
11 | 4171034363892 |
12 | 1563b4413710b |
13 | 7360ac175c44 |
14 | 3304621d5015 |
15 | 178b5996170b |
hex | bd827f52edb |
13023011221211 has 4 divisors (see below), whose sum is σ = 13070025702432. Its totient is φ = 12975996739992.
The previous prime is 13023011221133. The next prime is 13023011221223. The reversal of 13023011221211 is 11212211032031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13023011221211 - 230 = 13021937479387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13023011221291) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23507240195 + ... + 23507240748.
It is an arithmetic number, because the mean of its divisors is an integer number (3267506425608).
Almost surely, 213023011221211 is an apocalyptic number.
13023011221211 is a deficient number, since it is larger than the sum of its proper divisors (47014481221).
13023011221211 is an equidigital number, since it uses as much as digits as its factorization.
13023011221211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47014481220.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 13023011221211 its reverse (11212211032031), we get a palindrome (24235222253242).
The spelling of 13023011221211 in words is "thirteen trillion, twenty-three billion, eleven million, two hundred twenty-one thousand, two hundred eleven".
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