1302303400121 has 4 divisors (see below), whose sum is σ = 1302305801472. Its totient is φ = 1302300998772.

The previous prime is 1302303400091. The next prime is 1302303400147. The reversal of 1302303400121 is 1210043032031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1302303400121 - 2¹⁴ = 1302303383737 is a prime.

It is a super-3 number, since 3×1302303400121³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1302303400093 and 1302303400102.

It is not an unprimeable number, because it can be changed into a prime (1302303405121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40460 + ... + 1614386.

It is an arithmetic number, because the mean of its divisors is an integer number (325576450368).

Almost surely, 2^{1302303400121} is an apocalyptic number.

It is an amenable number.

1302303400121 is a deficient number, since it is larger than the sum of its proper divisors (2401351).

1302303400121 is an equidigital number, since it uses as much as digits as its factorization.

1302303400121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2401350.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1302303400121 its reverse (1210043032031), we get a palindrome (2512346432152).

The spelling of 1302303400121 in words is "one trillion, three hundred two billion, three hundred three million, four hundred thousand, one hundred twenty-one".