Search a number
-
+
1302311021113 = 2619714971203
BaseRepresentation
bin10010111100110111110…
…010010010101000111001
311121111111021221111012201
4102330313302102220321
5132314113110133423
62434135020510201
7163042324014304
oct22746762225071
94544437844181
101302311021113
114623416905a3
121904913ab361
1395a65b2ab5b
1447064485b3b
1523d21c722ad
hex12f37c92a39

1302311021113 has 4 divisors (see below), whose sum is σ = 1302316254288. Its totient is φ = 1302305787940.

The previous prime is 1302311021093. The next prime is 1302311021117. The reversal of 1302311021113 is 3111201132031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1302311021113 - 221 = 1302308923961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1302311021117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2223631 + ... + 2747572.

It is an arithmetic number, because the mean of its divisors is an integer number (325579063572).

Almost surely, 21302311021113 is an apocalyptic number.

It is an amenable number.

1302311021113 is a deficient number, since it is larger than the sum of its proper divisors (5233175).

1302311021113 is an equidigital number, since it uses as much as digits as its factorization.

1302311021113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5233174.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1302311021113 its reverse (3111201132031), we get a palindrome (4413512153144).

The spelling of 1302311021113 in words is "one trillion, three hundred two billion, three hundred eleven million, twenty-one thousand, one hundred thirteen".

Divisors: 1 261971 4971203 1302311021113