1302311113121 has 4 divisors (see below), whose sum is σ = 1318796064000. Its totient is φ = 1285826162244.

The previous prime is 1302311113099. The next prime is 1302311113123. The reversal of 1302311113121 is 1213111132031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1302311113121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1302311113093 and 1302311113102.

It is not an unprimeable number, because it can be changed into a prime (1302311113123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8242475321 + ... + 8242475478.

It is an arithmetic number, because the mean of its divisors is an integer number (329699016000).

Almost surely, 2^{1302311113121} is an apocalyptic number.

It is an amenable number.

1302311113121 is a deficient number, since it is larger than the sum of its proper divisors (16484950879).

1302311113121 is an equidigital number, since it uses as much as digits as its factorization.

1302311113121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16484950878.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1302311113121 its reverse (1213111132031), we get a palindrome (2515422245152).

The spelling of 1302311113121 in words is "one trillion, three hundred two billion, three hundred eleven million, one hundred thirteen thousand, one hundred twenty-one".