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13023112122017 is a prime number
BaseRepresentation
bin1011110110000010110111…
…1110001100111010100001
31201002222221002000222100122
42331200231332030322201
53201332313200401032
643410422441330025
72512613600401334
oct275405576147241
951088832028318
1013023112122017
114171086310088
121563b71a96915
137360c704376a
1433047177c61b
15178b63743012
hexbd82df8cea1

13023112122017 has 2 divisors, whose sum is σ = 13023112122018. Its totient is φ = 13023112122016.

The previous prime is 13023112121993. The next prime is 13023112122049. The reversal of 13023112122017 is 71022121132031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11276271456256 + 1746840665761 = 3358016^2 + 1321681^2 .

It is an emirp because it is prime and its reverse (71022121132031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13023112122017 - 216 = 13023112056481 is a prime.

It is a super-2 number, since 2×130231121220172 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13023112122217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511556061008 + 6511556061009.

It is an arithmetic number, because the mean of its divisors is an integer number (6511556061009).

Almost surely, 213023112122017 is an apocalyptic number.

It is an amenable number.

13023112122017 is a deficient number, since it is larger than the sum of its proper divisors (1).

13023112122017 is an equidigital number, since it uses as much as digits as its factorization.

13023112122017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 13023112122017 its reverse (71022121132031), we get a palindrome (84045233254048).

The spelling of 13023112122017 in words is "thirteen trillion, twenty-three billion, one hundred twelve million, one hundred twenty-two thousand, seventeen".