Search a number
-
+
130231131130097 is a prime number
BaseRepresentation
bin11101100111000111001100…
…010011110100100011110001
3122002002222022110000020102122
4131213013030103310203301
5114032201324032130342
61140551204500124025
736300613555663634
oct3547071423644361
9562088273006378
10130231131130097
113854a79244a218
12127337ba396615
1357889873c95aa
142423312a0bc1b
15100c925acb4d2
hex7671cc4f48f1

130231131130097 has 2 divisors, whose sum is σ = 130231131130098. Its totient is φ = 130231131130096.

The previous prime is 130231131129943. The next prime is 130231131130127. The reversal of 130231131130097 is 790031131132031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92616448577536 + 37614682552561 = 9623744^2 + 6133081^2 .

It is an emirp because it is prime and its reverse (790031131132031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130231131130097 is a prime.

It is not a weakly prime, because it can be changed into another prime (130231131130897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65115565565048 + 65115565565049.

It is an arithmetic number, because the mean of its divisors is an integer number (65115565565049).

Almost surely, 2130231131130097 is an apocalyptic number.

It is an amenable number.

130231131130097 is a deficient number, since it is larger than the sum of its proper divisors (1).

130231131130097 is an equidigital number, since it uses as much as digits as its factorization.

130231131130097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10206, while the sum is 35.

The spelling of 130231131130097 in words is "one hundred thirty trillion, two hundred thirty-one billion, one hundred thirty-one million, one hundred thirty thousand, ninety-seven".