Base | Representation |
---|---|
bin | 1011110110000010111010… |
… | …0001010011000100001011 |
3 | 1201002222221201100101201001 |
4 | 2331200232201103010023 |
5 | 3201332323024303001 |
6 | 43410423410435431 |
7 | 2512614041530225 |
oct | 275405641230413 |
9 | 51088851311631 |
10 | 13023121322251 |
11 | 4171090524387 |
12 | 1563b74b92b77 |
13 | 7360c8c152a1 |
14 | 330472a95415 |
15 | 178b6445e001 |
hex | bd82e85310b |
13023121322251 has 2 divisors, whose sum is σ = 13023121322252. Its totient is φ = 13023121322250.
The previous prime is 13023121322177. The next prime is 13023121322287. The reversal of 13023121322251 is 15222312132031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13023121322251 - 215 = 13023121289483 is a prime.
It is not a weakly prime, because it can be changed into another prime (13023121322291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511560661125 + 6511560661126.
It is an arithmetic number, because the mean of its divisors is an integer number (6511560661126).
Almost surely, 213023121322251 is an apocalyptic number.
13023121322251 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023121322251 is an equidigital number, since it uses as much as digits as its factorization.
13023121322251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 13023121322251 its reverse (15222312132031), we get a palindrome (28245433454282).
The spelling of 13023121322251 in words is "thirteen trillion, twenty-three billion, one hundred twenty-one million, three hundred twenty-two thousand, two hundred fifty-one".
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