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13023131002051 is a prime number
BaseRepresentation
bin1011110110000010111100…
…0110001110010011000011
31201002222222101120011220011
42331200233012032103003
53201332333014031201
643410424354125351
72512614220024222
oct275405706162303
951088871504804
1013023131002051
114171095a35a15
121563b78280857
137360cac24191
14330474094cb9
15178b65222151
hexbd82f18e4c3

13023131002051 has 2 divisors, whose sum is σ = 13023131002052. Its totient is φ = 13023131002050.

The previous prime is 13023131002039. The next prime is 13023131002103. The reversal of 13023131002051 is 15020013132031.

13023131002051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13023131002051 - 29 = 13023131001539 is a prime.

It is not a weakly prime, because it can be changed into another prime (13023131002351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511565501025 + 6511565501026.

It is an arithmetic number, because the mean of its divisors is an integer number (6511565501026).

Almost surely, 213023131002051 is an apocalyptic number.

13023131002051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13023131002051 is an equidigital number, since it uses as much as digits as its factorization.

13023131002051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 13023131002051 its reverse (15020013132031), we get a palindrome (28043144134082).

The spelling of 13023131002051 in words is "thirteen trillion, twenty-three billion, one hundred thirty-one million, two thousand, fifty-one".