Base | Representation |
---|---|
bin | 1011110110000010111100… |
… | …0110001110010011000011 |
3 | 1201002222222101120011220011 |
4 | 2331200233012032103003 |
5 | 3201332333014031201 |
6 | 43410424354125351 |
7 | 2512614220024222 |
oct | 275405706162303 |
9 | 51088871504804 |
10 | 13023131002051 |
11 | 4171095a35a15 |
12 | 1563b78280857 |
13 | 7360cac24191 |
14 | 330474094cb9 |
15 | 178b65222151 |
hex | bd82f18e4c3 |
13023131002051 has 2 divisors, whose sum is σ = 13023131002052. Its totient is φ = 13023131002050.
The previous prime is 13023131002039. The next prime is 13023131002103. The reversal of 13023131002051 is 15020013132031.
13023131002051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13023131002051 - 29 = 13023131001539 is a prime.
It is not a weakly prime, because it can be changed into another prime (13023131002351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511565501025 + 6511565501026.
It is an arithmetic number, because the mean of its divisors is an integer number (6511565501026).
Almost surely, 213023131002051 is an apocalyptic number.
13023131002051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023131002051 is an equidigital number, since it uses as much as digits as its factorization.
13023131002051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 13023131002051 its reverse (15020013132031), we get a palindrome (28043144134082).
The spelling of 13023131002051 in words is "thirteen trillion, twenty-three billion, one hundred thirty-one million, two thousand, fifty-one".
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