Base | Representation |
---|---|
bin | 1011110110000011100111… |
… | …1101010101011010110011 |
3 | 1201010000110002102212201012 |
4 | 2331200321331111122303 |
5 | 3201333221141040144 |
6 | 43410454423501135 |
7 | 2512621561614533 |
oct | 275407175253263 |
9 | 51100402385635 |
10 | 13023313221299 |
11 | 4171179883a37 |
12 | 15640092b77ab |
13 | 7361298c4214 |
14 | 3304903694c3 |
15 | 178b76217e9e |
hex | bd839f556b3 |
13023313221299 has 2 divisors, whose sum is σ = 13023313221300. Its totient is φ = 13023313221298.
The previous prime is 13023313221271. The next prime is 13023313221427. The reversal of 13023313221299 is 99212231332031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13023313221299 - 216 = 13023313155763 is a prime.
It is a super-2 number, since 2×130233132212992 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13023313221229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511656610649 + 6511656610650.
It is an arithmetic number, because the mean of its divisors is an integer number (6511656610650).
Almost surely, 213023313221299 is an apocalyptic number.
13023313221299 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023313221299 is an equidigital number, since it uses as much as digits as its factorization.
13023313221299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104976, while the sum is 41.
The spelling of 13023313221299 in words is "thirteen trillion, twenty-three billion, three hundred thirteen million, two hundred twenty-one thousand, two hundred ninety-nine".
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