Base | Representation |
---|---|
bin | 1011110110000011111111… |
… | …0010101010100100011001 |
3 | 1201010000200220121000002112 |
4 | 2331200333302222210121 |
5 | 3201333421214301031 |
6 | 43410512241242105 |
7 | 2512624160512253 |
oct | 275407762524431 |
9 | 51100626530075 |
10 | 13023411087641 |
11 | 417121a048409 |
12 | 1564036033335 |
13 | 736143c6b7b6 |
14 | 33049d362cd3 |
15 | 178b7eaea62b |
hex | bd83fcaa919 |
13023411087641 has 2 divisors, whose sum is σ = 13023411087642. Its totient is φ = 13023411087640.
The previous prime is 13023411087593. The next prime is 13023411087679. The reversal of 13023411087641 is 14678011432031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12769873662016 + 253537425625 = 3573496^2 + 503525^2 .
It is a cyclic number.
It is not a de Polignac number, because 13023411087641 - 214 = 13023411071257 is a prime.
It is not a weakly prime, because it can be changed into another prime (13023411077641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511705543820 + 6511705543821.
It is an arithmetic number, because the mean of its divisors is an integer number (6511705543821).
Almost surely, 213023411087641 is an apocalyptic number.
It is an amenable number.
13023411087641 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023411087641 is an equidigital number, since it uses as much as digits as its factorization.
13023411087641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 41.
The spelling of 13023411087641 in words is "thirteen trillion, twenty-three billion, four hundred eleven million, eighty-seven thousand, six hundred forty-one".
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