Base | Representation |
---|---|
bin | 1011110110000100000010… |
… | …0000111010001101000011 |
3 | 1201010000201202101220021011 |
4 | 2331201000200322031003 |
5 | 3201333432320212212 |
6 | 43410513353141351 |
7 | 2512624365532306 |
oct | 275410040721503 |
9 | 51100652356234 |
10 | 13023423210307 |
11 | 4171225978344 |
12 | 156403a0ba857 |
13 | 736146624583 |
14 | 3304a0bdab3d |
15 | 178b80be24a7 |
hex | bd84083a343 |
13023423210307 has 2 divisors, whose sum is σ = 13023423210308. Its totient is φ = 13023423210306.
The previous prime is 13023423210229. The next prime is 13023423210311. The reversal of 13023423210307 is 70301232432031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13023423210307 - 227 = 13023288992579 is a prime.
It is a super-2 number, since 2×130234232103072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13023423210337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511711605153 + 6511711605154.
It is an arithmetic number, because the mean of its divisors is an integer number (6511711605154).
Almost surely, 213023423210307 is an apocalyptic number.
13023423210307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023423210307 is an equidigital number, since it uses as much as digits as its factorization.
13023423210307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 31.
Adding to 13023423210307 its reverse (70301232432031), we get a palindrome (83324655642338).
The spelling of 13023423210307 in words is "thirteen trillion, twenty-three billion, four hundred twenty-three million, two hundred ten thousand, three hundred seven".
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