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13023423210307 is a prime number
BaseRepresentation
bin1011110110000100000010…
…0000111010001101000011
31201010000201202101220021011
42331201000200322031003
53201333432320212212
643410513353141351
72512624365532306
oct275410040721503
951100652356234
1013023423210307
114171225978344
12156403a0ba857
13736146624583
143304a0bdab3d
15178b80be24a7
hexbd84083a343

13023423210307 has 2 divisors, whose sum is σ = 13023423210308. Its totient is φ = 13023423210306.

The previous prime is 13023423210229. The next prime is 13023423210311. The reversal of 13023423210307 is 70301232432031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13023423210307 - 227 = 13023288992579 is a prime.

It is a super-2 number, since 2×130234232103072 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13023423210337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511711605153 + 6511711605154.

It is an arithmetic number, because the mean of its divisors is an integer number (6511711605154).

Almost surely, 213023423210307 is an apocalyptic number.

13023423210307 is a deficient number, since it is larger than the sum of its proper divisors (1).

13023423210307 is an equidigital number, since it uses as much as digits as its factorization.

13023423210307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 31.

Adding to 13023423210307 its reverse (70301232432031), we get a palindrome (83324655642338).

The spelling of 13023423210307 in words is "thirteen trillion, twenty-three billion, four hundred twenty-three million, two hundred ten thousand, three hundred seven".