Base | Representation |
---|---|
bin | 11101100111001010000101… |
… | …001001000110000111000001 |
3 | 122002010021022120001000001021 |
4 | 131213022011021012013001 |
5 | 114032224201404301421 |
6 | 1140552440312505441 |
7 | 36301053451554211 |
oct | 3547120511060701 |
9 | 562107276030037 |
10 | 130234232103361 |
11 | 38551033906341 |
12 | 127343249ab281 |
13 | 578905c9a5609 |
14 | 24235287ba241 |
15 | 100ca57e68341 |
hex | 7672852461c1 |
130234232103361 has 2 divisors, whose sum is σ = 130234232103362. Its totient is φ = 130234232103360.
The previous prime is 130234232103319. The next prime is 130234232103377. The reversal of 130234232103361 is 163301232432031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 117266807840400 + 12967424262961 = 10828980^2 + 3601031^2 .
It is a cyclic number.
It is not a de Polignac number, because 130234232103361 - 219 = 130234231579073 is a prime.
It is not a weakly prime, because it can be changed into another prime (130234232103961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65117116051680 + 65117116051681.
It is an arithmetic number, because the mean of its divisors is an integer number (65117116051681).
Almost surely, 2130234232103361 is an apocalyptic number.
It is an amenable number.
130234232103361 is a deficient number, since it is larger than the sum of its proper divisors (1).
130234232103361 is an equidigital number, since it uses as much as digits as its factorization.
130234232103361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 34.
Adding to 130234232103361 its reverse (163301232432031), we get a palindrome (293535464535392).
The spelling of 130234232103361 in words is "one hundred thirty trillion, two hundred thirty-four billion, two hundred thirty-two million, one hundred three thousand, three hundred sixty-one".
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