Base | Representation |
---|---|
bin | 11101100111001010001001… |
… | …111110000101011101100011 |
3 | 122002010021112012110012221102 |
4 | 131213022021332011131203 |
5 | 114032224333123300303 |
6 | 1140552452324545015 |
7 | 36301055454213311 |
oct | 3547121176053543 |
9 | 562107465405842 |
10 | 130234313103203 |
11 | 385510755aa761 |
12 | 12734347b5216b |
13 | 57890736c5b0a |
14 | 24235354630b1 |
15 | 100ca60118288 |
hex | 767289f85763 |
130234313103203 has 2 divisors, whose sum is σ = 130234313103204. Its totient is φ = 130234313103202.
The previous prime is 130234313103137. The next prime is 130234313103221. The reversal of 130234313103203 is 302301313432031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130234313103203 - 214 = 130234313086819 is a prime.
It is a super-2 number, since 2×1302343131032032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130234313103263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65117156551601 + 65117156551602.
It is an arithmetic number, because the mean of its divisors is an integer number (65117156551602).
Almost surely, 2130234313103203 is an apocalyptic number.
130234313103203 is a deficient number, since it is larger than the sum of its proper divisors (1).
130234313103203 is an equidigital number, since it uses as much as digits as its factorization.
130234313103203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 29.
Adding to 130234313103203 its reverse (302301313432031), we get a palindrome (432535626535234).
The spelling of 130234313103203 in words is "one hundred thirty trillion, two hundred thirty-four billion, three hundred thirteen million, one hundred three thousand, two hundred three".
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