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130234412251 = 1271025467813
BaseRepresentation
bin111100101001010010…
…0110110110011011011
3110110011021000121210001
41321102210312303123
54113210002143001
6135455011233431
712260221144666
oct1712244666333
9413137017701
10130234412251
1150260a26569
12212a72a8877
13c38661a1c8
1464366886dd
1535c3719001
hex1e52936cdb

130234412251 has 4 divisors (see below), whose sum is σ = 131259880192. Its totient is φ = 129208944312.

The previous prime is 130234412249. The next prime is 130234412257. The reversal of 130234412251 is 152214432031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130234412251 - 21 = 130234412249 is a prime.

It is a super-2 number, since 2×1302344122512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130234412257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 512733780 + ... + 512734033.

It is an arithmetic number, because the mean of its divisors is an integer number (32814970048).

Almost surely, 2130234412251 is an apocalyptic number.

130234412251 is a deficient number, since it is larger than the sum of its proper divisors (1025467941).

130234412251 is a wasteful number, since it uses less digits than its factorization.

130234412251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1025467940.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 130234412251 its reverse (152214432031), we get a palindrome (282448844282).

The spelling of 130234412251 in words is "one hundred thirty billion, two hundred thirty-four million, four hundred twelve thousand, two hundred fifty-one".

Divisors: 1 127 1025467813 130234412251