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13024421151307 = 43130219074597
BaseRepresentation
bin1011110110000111101111…
…1111110000001001001011
31201010010022022012112221221
42331201323333300021023
53201343003303320212
643411200402342511
72512661204066266
oct275417377601113
951103268175857
1013024421151307
114171698215175
12156427835aa37
137362752c04c7
1433055756dcdd
15178bdd618807
hexbd87bff024b

13024421151307 has 4 divisors (see below), whose sum is σ = 13054640226336. Its totient is φ = 12994202076280.

The previous prime is 13024421151299. The next prime is 13024421151319. The reversal of 13024421151307 is 70315112442031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13024421151307 - 23 = 13024421151299 is a prime.

It is a super-2 number, since 2×130244211513072 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13024421151367) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15109536868 + ... + 15109537729.

It is an arithmetic number, because the mean of its divisors is an integer number (3263660056584).

Almost surely, 213024421151307 is an apocalyptic number.

13024421151307 is a deficient number, since it is larger than the sum of its proper divisors (30219075029).

13024421151307 is an equidigital number, since it uses as much as digits as its factorization.

13024421151307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30219075028.

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 13024421151307 its reverse (70315112442031), we get a palindrome (83339533593338).

The spelling of 13024421151307 in words is "thirteen trillion, twenty-four billion, four hundred twenty-one million, one hundred fifty-one thousand, three hundred seven".

Divisors: 1 431 30219074597 13024421151307