Base | Representation |
---|---|
bin | 111100101001110011… |
… | …0010111001010011001 |
3 | 110110012110100001012102 |
4 | 1321103212113022121 |
5 | 4113223401143103 |
6 | 135500423253145 |
7 | 12260520124565 |
oct | 1712346271231 |
9 | 413173301172 |
10 | 130251584153 |
11 | 5026a695019 |
12 | 212b0baa1b5 |
13 | c38a0502b2 |
14 | 6438a786a5 |
15 | 35c4eabe88 |
hex | 1e53997299 |
130251584153 has 2 divisors, whose sum is σ = 130251584154. Its totient is φ = 130251584152.
The previous prime is 130251584143. The next prime is 130251584167. The reversal of 130251584153 is 351485152031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105526223104 + 24725361049 = 324848^2 + 157243^2 .
It is a cyclic number.
It is not a de Polignac number, because 130251584153 - 212 = 130251580057 is a prime.
It is not a weakly prime, because it can be changed into another prime (130251584143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65125792076 + 65125792077.
It is an arithmetic number, because the mean of its divisors is an integer number (65125792077).
Almost surely, 2130251584153 is an apocalyptic number.
It is an amenable number.
130251584153 is a deficient number, since it is larger than the sum of its proper divisors (1).
130251584153 is an equidigital number, since it uses as much as digits as its factorization.
130251584153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 38.
The spelling of 130251584153 in words is "one hundred thirty billion, two hundred fifty-one million, five hundred eighty-four thousand, one hundred fifty-three".
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