Base | Representation |
---|---|
bin | 11101100111011010110001… |
… | …011100010100110111101001 |
3 | 122002011222120122112012220122 |
4 | 131213122301130110313221 |
5 | 114033022403213224431 |
6 | 1141005003011133025 |
7 | 36302256554506100 |
oct | 3547326134246751 |
9 | 562158518465818 |
10 | 130252155211241 |
11 | 385586a0a4a598 |
12 | 127378a72a4175 |
13 | 578a957cc32ab |
14 | 2424348d0d037 |
15 | 100d2566d3a7b |
hex | 7676b1714de9 |
130252155211241 has 24 divisors (see below), whose sum is σ = 154900962251136. Its totient is φ = 109156750614240.
The previous prime is 130252155211237. The next prime is 130252155211259. The reversal of 130252155211241 is 142112551252031.
It is not a de Polignac number, because 130252155211241 - 22 = 130252155211237 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (130252155211741) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 26887166 + ... + 31359591.
It is an arithmetic number, because the mean of its divisors is an integer number (6454206760464).
Almost surely, 2130252155211241 is an apocalyptic number.
It is an amenable number.
130252155211241 is a deficient number, since it is larger than the sum of its proper divisors (24648807039895).
130252155211241 is an equidigital number, since it uses as much as digits as its factorization.
130252155211241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58247789 (or 58247782 counting only the distinct ones).
The product of its (nonzero) digits is 24000, while the sum is 35.
The spelling of 130252155211241 in words is "one hundred thirty trillion, two hundred fifty-two billion, one hundred fifty-five million, two hundred eleven thousand, two hundred forty-one".
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