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13026136273049 is a prime number
BaseRepresentation
bin1011110110001110001000…
…1110011011000010011001
31201010021201211111202200102
42331203202032123002121
53201410011341214144
643412042511345145
72513051541302234
oct275434216330231
951107654452612
1013026136273049
114172398376559
1215646768221b5
13736489732943
1433067b27041b
15178c8dea7b4e
hexbd8e239b099

13026136273049 has 2 divisors, whose sum is σ = 13026136273050. Its totient is φ = 13026136273048.

The previous prime is 13026136272949. The next prime is 13026136273061. The reversal of 13026136273049 is 94037263162031.

13026136273049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11983505358400 + 1042630914649 = 3461720^2 + 1021093^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13026136273049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13026136272994 and 13026136273012.

It is not a weakly prime, because it can be changed into another prime (13026136273079) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6513068136524 + 6513068136525.

It is an arithmetic number, because the mean of its divisors is an integer number (6513068136525).

Almost surely, 213026136273049 is an apocalyptic number.

It is an amenable number.

13026136273049 is a deficient number, since it is larger than the sum of its proper divisors (1).

13026136273049 is an equidigital number, since it uses as much as digits as its factorization.

13026136273049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 979776, while the sum is 47.

The spelling of 13026136273049 in words is "thirteen trillion, twenty-six billion, one hundred thirty-six million, two hundred seventy-three thousand, forty-nine".