Base | Representation |
---|---|
bin | 11101100111100100010101… |
… | …000110001001011011011011 |
3 | 122002012222001210222210221212 |
4 | 131213210111012021123123 |
5 | 114033204412231202103 |
6 | 1141013421150053335 |
7 | 36303102061644215 |
oct | 3547442506113333 |
9 | 562188053883855 |
10 | 130262417053403 |
11 | 38561a87546488 |
12 | 1273988baaa24b |
13 | 578b90200b34b |
14 | 2424a3db515b5 |
15 | 100d6575647d8 |
hex | 7679151896db |
130262417053403 has 2 divisors, whose sum is σ = 130262417053404. Its totient is φ = 130262417053402.
The previous prime is 130262417053387. The next prime is 130262417053463. The reversal of 130262417053403 is 304350714262031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130262417053403 - 24 = 130262417053387 is a prime.
It is not a weakly prime, because it can be changed into another prime (130262417053463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65131208526701 + 65131208526702.
It is an arithmetic number, because the mean of its divisors is an integer number (65131208526702).
Almost surely, 2130262417053403 is an apocalyptic number.
130262417053403 is a deficient number, since it is larger than the sum of its proper divisors (1).
130262417053403 is an equidigital number, since it uses as much as digits as its factorization.
130262417053403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 41.
The spelling of 130262417053403 in words is "one hundred thirty trillion, two hundred sixty-two billion, four hundred seventeen million, fifty-three thousand, four hundred three".
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