Base | Representation |
---|---|
bin | 11000010001001010… |
… | …11101000101000011 |
3 | 1020122000020122000011 |
4 | 30020211131011003 |
5 | 203140402004201 |
6 | 5552503205351 |
7 | 640604101063 |
oct | 141045350503 |
9 | 36560218004 |
10 | 13028938051 |
11 | 558654aaa8 |
12 | 2637446857 |
13 | 12c83944cc |
14 | 8b853d3a3 |
15 | 513c6b151 |
hex | 30895d143 |
13028938051 has 2 divisors, whose sum is σ = 13028938052. Its totient is φ = 13028938050.
The previous prime is 13028938033. The next prime is 13028938061. The reversal of 13028938051 is 15083982031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13028938051 - 227 = 12894720323 is a prime.
It is a super-3 number, since 3×130289380513 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13028937995 and 13028938013.
It is not a weakly prime, because it can be changed into another prime (13028938061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6514469025 + 6514469026.
It is an arithmetic number, because the mean of its divisors is an integer number (6514469026).
Almost surely, 213028938051 is an apocalyptic number.
13028938051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13028938051 is an equidigital number, since it uses as much as digits as its factorization.
13028938051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 40.
The spelling of 13028938051 in words is "thirteen billion, twenty-eight million, nine hundred thirty-eight thousand, fifty-one".
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