1302896895473 has 2 divisors, whose sum is σ = 1302896895474. Its totient is φ = 1302896895472.

The previous prime is 1302896895463. The next prime is 1302896895479. The reversal of 1302896895473 is 3745986982031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1212216414049 + 90680481424 = 1101007^2 + 301132^2 .

It is a cyclic number.

It is not a de Polignac number, because 1302896895473 - 2⁴ = 1302896895457 is a prime.

It is not a weakly prime, because it can be changed into another prime (1302896895479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651448447736 + 651448447737.

It is an arithmetic number, because the mean of its divisors is an integer number (651448447737).

It is a 1-persistent number, because it is pandigital, but 2⋅1302896895473 = 2605793790946 is not.

Almost surely, 2^{1302896895473} is an apocalyptic number.

It is an amenable number.

1302896895473 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302896895473 is an equidigital number, since it uses as much as digits as its factorization.

1302896895473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78382080, while the sum is 65.

The spelling of 1302896895473 in words is "one trillion, three hundred two billion, eight hundred ninety-six million, eight hundred ninety-five thousand, four hundred seventy-three".