13030001001217 has 2 divisors, whose sum is σ = 13030001001218. Its totient is φ = 13030001001216.

The previous prime is 13030001001169. The next prime is 13030001001221. The reversal of 13030001001217 is 71210010003031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7139749664961 + 5890251336256 = 2672031^2 + 2426984^2 .

It is a cyclic number.

It is not a de Polignac number, because 13030001001217 - 2⁴³ = 4233907979009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13030001001194 and 13030001001203.

It is not a weakly prime, because it can be changed into another prime (13030001002217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515000500608 + 6515000500609.

It is an arithmetic number, because the mean of its divisors is an integer number (6515000500609).

Almost surely, 2^{13030001001217} is an apocalyptic number.

It is an amenable number.

13030001001217 is a deficient number, since it is larger than the sum of its proper divisors (1).

13030001001217 is an equidigital number, since it uses as much as digits as its factorization.

13030001001217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126, while the sum is 19.

Adding to 13030001001217 its reverse (71210010003031), we get a palindrome (84240011004248).

The spelling of 13030001001217 in words is "thirteen trillion, thirty billion, one million, one thousand, two hundred seventeen".