Base | Representation |
---|---|
bin | 10010111101100000111… |
… | …010010111000010001011 |
3 | 11121120021101021011012221 |
4 | 102331200322113002023 |
5 | 132322021224031443 |
6 | 2434331305314511 |
7 | 163065402526612 |
oct | 22754072270213 |
9 | 4546241234187 |
10 | 1303001002123 |
11 | 462666107537 |
12 | 190644495a37 |
13 | 95b45a6cb42 |
14 | 470cbd72879 |
15 | 23d62615eed |
hex | 12f60e9708b |
1303001002123 has 2 divisors, whose sum is σ = 1303001002124. Its totient is φ = 1303001002122.
The previous prime is 1303001002111. The next prime is 1303001002129. The reversal of 1303001002123 is 3212001003031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1303001002123 - 25 = 1303001002091 is a prime.
It is a super-2 number, since 2×13030010021232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1303001002097 and 1303001002106.
It is not a weakly prime, because it can be changed into another prime (1303001002129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651500501061 + 651500501062.
It is an arithmetic number, because the mean of its divisors is an integer number (651500501062).
Almost surely, 21303001002123 is an apocalyptic number.
1303001002123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303001002123 is an equidigital number, since it uses as much as digits as its factorization.
1303001002123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 1303001002123 its reverse (3212001003031), we get a palindrome (4515002005154).
The spelling of 1303001002123 in words is "one trillion, three hundred three billion, one million, two thousand, one hundred twenty-three".
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