Base | Representation |
---|---|
bin | 1011110110011100101001… |
… | …1000100011001010100001 |
3 | 1201010122210021120200110121 |
4 | 2331213022120203022201 |
5 | 3201441000444220024 |
6 | 43413525210200241 |
7 | 2513250215060434 |
oct | 275471230431241 |
9 | 51118707520417 |
10 | 13030031241889 |
11 | 4174006a42272 |
12 | 1565383123081 |
13 | 73695a66b82c |
14 | 33092a68381b |
15 | 178e1add28e4 |
hex | bd9ca6232a1 |
13030031241889 has 2 divisors, whose sum is σ = 13030031241890. Its totient is φ = 13030031241888.
The previous prime is 13030031241863. The next prime is 13030031241907. The reversal of 13030031241889 is 98814213003031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9567391334400 + 3462639907489 = 3093120^2 + 1860817^2 .
It is a cyclic number.
It is not a de Polignac number, because 13030031241889 - 239 = 12480275428001 is a prime.
It is not a weakly prime, because it can be changed into another prime (13030031241859) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515015620944 + 6515015620945.
It is an arithmetic number, because the mean of its divisors is an integer number (6515015620945).
Almost surely, 213030031241889 is an apocalyptic number.
It is an amenable number.
13030031241889 is a deficient number, since it is larger than the sum of its proper divisors (1).
13030031241889 is an equidigital number, since it uses as much as digits as its factorization.
13030031241889 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 43.
The spelling of 13030031241889 in words is "thirteen trillion, thirty billion, thirty-one million, two hundred forty-one thousand, eight hundred eighty-nine".
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