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13030102113 = 37620481053
BaseRepresentation
bin11000010001010011…
…11001010001100001
31020122002102202210120
430020221321101201
5203141201231423
65552544150453
7640620016620
oct141051712141
936562382716
1013030102113
115587175636
122637908429
1312c86b12c2
148b87636b7
15513deaee3
hex308a79461

13030102113 has 8 divisors (see below), whose sum is σ = 19855393728. Its totient is φ = 7445772624.

The previous prime is 13030102103. The next prime is 13030102121. The reversal of 13030102113 is 31120103031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13030102113 - 212 = 13030098017 is a prime.

It is a super-2 number, since 2×130301021132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13030102092 and 13030102101.

It is not an unprimeable number, because it can be changed into a prime (13030102103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 310240506 + ... + 310240547.

It is an arithmetic number, because the mean of its divisors is an integer number (2481924216).

Almost surely, 213030102113 is an apocalyptic number.

It is an amenable number.

13030102113 is a deficient number, since it is larger than the sum of its proper divisors (6825291615).

13030102113 is an equidigital number, since it uses as much as digits as its factorization.

13030102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 620481063.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13030102113 its reverse (31120103031), we get a palindrome (44150205144).

The spelling of 13030102113 in words is "thirteen billion, thirty million, one hundred two thousand, one hundred thirteen".

Divisors: 1 3 7 21 620481053 1861443159 4343367371 13030102113