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1303031112113 is a prime number
BaseRepresentation
bin10010111101100010101…
…101001110000110110001
311121120100110220220100202
4102331202231032012301
5132322101431041423
62434334302524545
7163066216464053
oct22754255160661
94546313826322
101303031112113
11462681102625
12190652596755
1395b4c082bc3
14470d1d6d8d3
1523d650b2728
hex12f62b4e1b1

1303031112113 has 2 divisors, whose sum is σ = 1303031112114. Its totient is φ = 1303031112112.

The previous prime is 1303031112107. The next prime is 1303031112139. The reversal of 1303031112113 is 3112111303031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1296337090624 + 6694021489 = 1138568^2 + 81817^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1303031112113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1303031112613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651515556056 + 651515556057.

It is an arithmetic number, because the mean of its divisors is an integer number (651515556057).

Almost surely, 21303031112113 is an apocalyptic number.

It is an amenable number.

1303031112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303031112113 is an equidigital number, since it uses as much as digits as its factorization.

1303031112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1303031112113 its reverse (3112111303031), we get a palindrome (4415142415144).

The spelling of 1303031112113 in words is "one trillion, three hundred three billion, thirty-one million, one hundred twelve thousand, one hundred thirteen".