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130305404051 = 711835287381
BaseRepresentation
bin111100101011011001…
…1101010110010010011
3110110100012121101012222
41321112303222302103
54113331140412201
6135510025011255
712262042442114
oct1712663526223
9413305541188
10130305404051
1150298004779
1221307023b2b
13c3982452a4
146441c8820b
1535c9a8d91b
hex1e56ceac93

130305404051 has 4 divisors (see below), whose sum is σ = 132140691504. Its totient is φ = 128470116600.

The previous prime is 130305404011. The next prime is 130305404077. The reversal of 130305404051 is 150404503031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 150404503031 = 207409725159.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130305404051 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130305404051.

It is not an unprimeable number, because it can be changed into a prime (130305404011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 917643620 + ... + 917643761.

It is an arithmetic number, because the mean of its divisors is an integer number (33035172876).

Almost surely, 2130305404051 is an apocalyptic number.

130305404051 is a deficient number, since it is larger than the sum of its proper divisors (1835287453).

130305404051 is an equidigital number, since it uses as much as digits as its factorization.

130305404051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1835287452.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 130305404051 its reverse (150404503031), we get a palindrome (280709907082).

The spelling of 130305404051 in words is "one hundred thirty billion, three hundred five million, four hundred four thousand, fifty-one".

Divisors: 1 71 1835287381 130305404051