Search a number
-
+
130305838561 is a prime number
BaseRepresentation
bin111100101011011010…
…1010100110111100001
3110110100020102110020221
41321112311110313201
54113331243313221
6135510042203041
712262046231653
oct1712665246741
9413306373227
10130305838561
1150298281178
12213071b3481
13c398367cb2
146441d5c6d3
1535c9b27541
hex1e56d54de1

130305838561 has 2 divisors, whose sum is σ = 130305838562. Its totient is φ = 130305838560.

The previous prime is 130305838391. The next prime is 130305838583. The reversal of 130305838561 is 165838503031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120339610000 + 9966228561 = 346900^2 + 99831^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130305838561 is a prime.

It is a super-2 number, since 2×1303058385612 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130306838561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65152919280 + 65152919281.

It is an arithmetic number, because the mean of its divisors is an integer number (65152919281).

Almost surely, 2130305838561 is an apocalyptic number.

It is an amenable number.

130305838561 is a deficient number, since it is larger than the sum of its proper divisors (1).

130305838561 is an equidigital number, since it uses as much as digits as its factorization.

130305838561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 43.

The spelling of 130305838561 in words is "one hundred thirty billion, three hundred five million, eight hundred thirty-eight thousand, five hundred sixty-one".