Base | Representation |
---|---|
bin | 111100101011011010… |
… | …1010100110111100001 |
3 | 110110100020102110020221 |
4 | 1321112311110313201 |
5 | 4113331243313221 |
6 | 135510042203041 |
7 | 12262046231653 |
oct | 1712665246741 |
9 | 413306373227 |
10 | 130305838561 |
11 | 50298281178 |
12 | 213071b3481 |
13 | c398367cb2 |
14 | 6441d5c6d3 |
15 | 35c9b27541 |
hex | 1e56d54de1 |
130305838561 has 2 divisors, whose sum is σ = 130305838562. Its totient is φ = 130305838560.
The previous prime is 130305838391. The next prime is 130305838583. The reversal of 130305838561 is 165838503031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 120339610000 + 9966228561 = 346900^2 + 99831^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130305838561 is a prime.
It is a super-2 number, since 2×1303058385612 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130306838561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65152919280 + 65152919281.
It is an arithmetic number, because the mean of its divisors is an integer number (65152919281).
Almost surely, 2130305838561 is an apocalyptic number.
It is an amenable number.
130305838561 is a deficient number, since it is larger than the sum of its proper divisors (1).
130305838561 is an equidigital number, since it uses as much as digits as its factorization.
130305838561 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 259200, while the sum is 43.
The spelling of 130305838561 in words is "one hundred thirty billion, three hundred five million, eight hundred thirty-eight thousand, five hundred sixty-one".
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