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130310122223113 = 719979775355061
BaseRepresentation
bin11101101000010000110000…
…100010111011011000001001
3122002101112012110200112020021
4131220100300202323120021
5114040000112242114423
61141051351013300441
736306411210126520
oct3550206042733011
9562345173615207
10130310122223113
11385802378a9578
1212746b84334721
1357932654c6011
14242708779b4b7
15100e9ea70995d
hex7684308bb609

130310122223113 has 8 divisors (see below), whose sum is σ = 156764056809920. Its totient is φ = 105815738346480.

The previous prime is 130310122223041. The next prime is 130310122223119. The reversal of 130310122223113 is 311322221013031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130310122223113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130310122223119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 489887677398 + ... + 489887677663.

It is an arithmetic number, because the mean of its divisors is an integer number (19595507101240).

Almost surely, 2130310122223113 is an apocalyptic number.

It is an amenable number.

130310122223113 is a deficient number, since it is larger than the sum of its proper divisors (26453934586807).

130310122223113 is an equidigital number, since it uses as much as digits as its factorization.

130310122223113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 979775355087.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 130310122223113 its reverse (311322221013031), we get a palindrome (441632343236144).

The spelling of 130310122223113 in words is "one hundred thirty trillion, three hundred ten billion, one hundred twenty-two million, two hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 7 19 133 979775355061 6858427485427 18615731746159 130310122223113