Base | Representation |
---|---|
bin | 11101101000010000110000… |
… | …100010111011011000001001 |
3 | 122002101112012110200112020021 |
4 | 131220100300202323120021 |
5 | 114040000112242114423 |
6 | 1141051351013300441 |
7 | 36306411210126520 |
oct | 3550206042733011 |
9 | 562345173615207 |
10 | 130310122223113 |
11 | 385802378a9578 |
12 | 12746b84334721 |
13 | 57932654c6011 |
14 | 242708779b4b7 |
15 | 100e9ea70995d |
hex | 7684308bb609 |
130310122223113 has 8 divisors (see below), whose sum is σ = 156764056809920. Its totient is φ = 105815738346480.
The previous prime is 130310122223041. The next prime is 130310122223119. The reversal of 130310122223113 is 311322221013031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130310122223113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130310122223119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 489887677398 + ... + 489887677663.
It is an arithmetic number, because the mean of its divisors is an integer number (19595507101240).
Almost surely, 2130310122223113 is an apocalyptic number.
It is an amenable number.
130310122223113 is a deficient number, since it is larger than the sum of its proper divisors (26453934586807).
130310122223113 is an equidigital number, since it uses as much as digits as its factorization.
130310122223113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 979775355087.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 130310122223113 its reverse (311322221013031), we get a palindrome (441632343236144).
The spelling of 130310122223113 in words is "one hundred thirty trillion, three hundred ten billion, one hundred twenty-two million, two hundred twenty-three thousand, one hundred thirteen".
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