Base | Representation |
---|---|
bin | 1011110110100000101010… |
… | …1100001100011001001011 |
3 | 1201010202120110201001021121 |
4 | 2331220022230030121023 |
5 | 3202000203143231243 |
6 | 43414224230420111 |
7 | 2513316025356502 |
oct | 275501254143113 |
9 | 51122513631247 |
10 | 13031110133323 |
11 | 417450aa4a387 |
12 | 1565624501637 |
13 | 736aa003b629 |
14 | 3309cda89839 |
15 | 178e809991ed |
hex | bda0ab0c64b |
13031110133323 has 4 divisors (see below), whose sum is σ = 13480458758640. Its totient is φ = 12581761508008.
The previous prime is 13031110133233. The next prime is 13031110133329. The reversal of 13031110133323 is 32333101113031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13031110133323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13031110133329) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224674312615 + ... + 224674312672.
It is an arithmetic number, because the mean of its divisors is an integer number (3370114689660).
Almost surely, 213031110133323 is an apocalyptic number.
13031110133323 is a deficient number, since it is larger than the sum of its proper divisors (449348625317).
13031110133323 is an equidigital number, since it uses as much as digits as its factorization.
13031110133323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 449348625316.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 13031110133323 its reverse (32333101113031), we get a palindrome (45364211246354).
The spelling of 13031110133323 in words is "thirteen trillion, thirty-one billion, one hundred ten million, one hundred thirty-three thousand, three hundred twenty-three".
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