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13031112049 is a prime number
BaseRepresentation
bin11000010001011011…
…01111110101110001
31020122011100002011121
430020231233311301
5203141431041144
65553021542241
7640631424214
oct141055576561
936564302147
1013031112049
1155877a539a
122638114981
1312c8975bb7
148b894777b
1551404a384
hex308b6fd71

13031112049 has 2 divisors, whose sum is σ = 13031112050. Its totient is φ = 13031112048.

The previous prime is 13031111921. The next prime is 13031112077. The reversal of 13031112049 is 94021113031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12874987024 + 156125025 = 113468^2 + 12495^2 .

It is a cyclic number.

It is not a de Polignac number, because 13031112049 - 27 = 13031111921 is a prime.

It is a super-3 number, since 3×130311120493 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13031112079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515556024 + 6515556025.

It is an arithmetic number, because the mean of its divisors is an integer number (6515556025).

Almost surely, 213031112049 is an apocalyptic number.

It is an amenable number.

13031112049 is a deficient number, since it is larger than the sum of its proper divisors (1).

13031112049 is an equidigital number, since it uses as much as digits as its factorization.

13031112049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 13031112049 in words is "thirteen billion, thirty-one million, one hundred twelve thousand, forty-nine".