Base | Representation |
---|---|
bin | 1011110110100001000101… |
… | …0111110001110100001001 |
3 | 1201010202212021121202011101 |
4 | 2331220101113301310021 |
5 | 3202000420342101324 |
6 | 43414243313101401 |
7 | 2513321556201061 |
oct | 275502127616411 |
9 | 51122767552141 |
10 | 13031222222089 |
11 | 4174568248325 |
12 | 1565655b57861 |
13 | 736aba325646 |
14 | 330a009063a1 |
15 | 178e8a73a944 |
hex | bda115f1d09 |
13031222222089 has 2 divisors, whose sum is σ = 13031222222090. Its totient is φ = 13031222222088.
The previous prime is 13031222222077. The next prime is 13031222222153. The reversal of 13031222222089 is 98022222213031.
13031222222089 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12962844156025 + 68378066064 = 3600395^2 + 261492^2 .
It is a cyclic number.
It is not a de Polignac number, because 13031222222089 - 237 = 12893783268617 is a prime.
It is not a weakly prime, because it can be changed into another prime (13031222225089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515611111044 + 6515611111045.
It is an arithmetic number, because the mean of its divisors is an integer number (6515611111045).
Almost surely, 213031222222089 is an apocalyptic number.
It is an amenable number.
13031222222089 is a deficient number, since it is larger than the sum of its proper divisors (1).
13031222222089 is an equidigital number, since it uses as much as digits as its factorization.
13031222222089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 37.
The spelling of 13031222222089 in words is "thirteen trillion, thirty-one billion, two hundred twenty-two million, two hundred twenty-two thousand, eighty-nine".
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